Example 1: Finding the Standard Equation of a Parabola
Find the standard form of the equation of the parabola with vertex (2,1) and focus (2,4).
Because the axis of the parabola is vertical, consider the equation (x-h)^2 = 4p(y-k) where h = 2, k = 1, and p = 4-1 = 3. Thus, the standard form is (x-2)^2 = 12(y-1).
Example 2: Finding the Focus of a Parabola
Find the focus of the parabola given by y = -1/2(x)^2 - x + 1/2. To find the focus, convert to standard form by completing the square. The steps are listed as follows:
y = -1/2(x)^2 - x + 1/2 (Original equation)
-2y = x^2 + 2x - 1 (Multiply both sides by -2)
1 - 2y = x^2 + 2x (Group the terms)
2 - 2y = x^2 + 2x + 1 (Complete the square)
-2(y - 1) = (x + 1)^2 (Standard form)
Comparing this equation with (x - h)^2 = 4p(y - k), you can conclude that h = -1, k = 1, and p = -1/2. Because p is negative, the parabola opens downward. The focus is (h, k + p) = (-1, 1/2).
Example 3: Vertex at the Origin
Find the standard equation of the parabola with vertex at the origin and focus (2,0). The axis of the parabola is horizontal, passing through (0,0) and (2,0). Thus, the standard form is y^2 = 4px where h = k = 0 and p = 2. The equation is y^2 = 8x.
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