If n! is defined as the product of all positive intergers from 1 to n, then:
1! = 1 x 1 = 1
2! = 1 x 2 = 2
3! = 1 x 2 x 3 = 6
4! = 1 x 2 x 3 x 4 = 24
n! = 1 x 2 x 3 x 4... x (n-2) x (n-1) x n
And so forth.
Logically, n! can also be expressed n x (n-1)!
Therefore, at n = 1, using n! = n x (n-1)!
1! = 1 x (1-1)!
1! = 1 x 0!
This simplifies to 1 = 0!
And there you go, a mathematical explanation for 0! = 1.
i'm glad somebody researched this because i was curious, but didn't want to research it myself! hahaha it makes sense now
ReplyDeleteI researched it to and got the same thing!
ReplyDelete